x^2-38x+156=0

Solution for x^2-38x+156=0 equation:

x^2-38x+156=0

a = 1; b = -38; c = +156;
Δ = b2-4ac
Δ = -382-4·1·156
Δ = 820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{820}=\sqrt{4*205}=\sqrt{4}*\sqrt{205}=2\sqrt{205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-2\sqrt{205}}{2*1}=\frac{38-2\sqrt{205}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+2\sqrt{205}}{2*1}=\frac{38+2\sqrt{205}}{2}
$